x^2-5.3x+1=0

Solution for x^2-5.3x+1=0 equation:

x^2-5.3x+1=0

a = 1; b = -5.3; c = +1;
Δ = b2-4ac
Δ = -5.32-4·1·1
Δ = 24.09
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5.3)-\sqrt{24.09}}{2*1}=\frac{5.3-\sqrt{24.09}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5.3)+\sqrt{24.09}}{2*1}=\frac{5.3+\sqrt{24.09}}{2}
$